6.step one and you will 6.step three Quiz

Explanation: SV = VU 2x + 11 = 8x – step 1 8x – 2x = 11 + 1 6x = twelve x = 2 Uv = 8(2) – 1 = fifteen

Explanation: 5x – cuatro = 4x + 3 times = eight ?JGK = 4(7) + step three = 30 meters?GJK = 180 – (31 + 90) = 180 – 121 = 59

Explanation: Recall the circumcentre regarding a triangle are equidistant from the vertices of a triangle. Then PA = PB = Desktop computer PA? = PB? = PC? PA? = PB? (x + 4)? + (y – 2)? = (x + 4)? + (y + 4)? x? + 8x + 16 + y? – 4y + cuatro = x? + 8x + sixteen + y? + 8y + sixteen 12y = -twelve y = -1 PB? = PC? (x + 4)? + (y + 4)? = (x – 0)? + (y + 4)? x? + 8x + 16 + y? + 8y + 16 = x? + y? + 8y + sixteen 8x = -16 x = -dos The latest circumcenter try (-2, -1)

Explanation: Keep in mind that the circumcentre away from a beneficial triangle are equidistant about vertices out-of an effective triangle. Help D(step 3, 5), E(7, 9), F(eleven, 5) function as the vertices of your provided triangle and you may assist P(x,y) be the circumcentre of triangle. After that PD = PE = PF PD? = PE? = PF? PD? = PE? (x – 3)? + (y – 5)? = (x – 7)? + (y – 9)? x? – 6x + nine + y? – 10y + twenty-five = x? – 14x + forty two + y? – 18y + 81 -6x + 14x – 10y + 18y = 130 – 34 8x + 8y = 96 x + y = a dozen – (i) PE? = PF? (x – 7)? + (y – 9)? = (x – 11)? + (y – 5)? x? – 14x + 44 + y? – 18y + 81 = x? – 22x + 121 + y? – 10y + 25 -14x + 22x – 18y + 10y = 146 – 130 8x – 8y = sixteen x – y = dos – (ii) Create (i) (ii) x + y + x – y = twelve + 2 2x = 14 x = eight Lay x = seven in (i) eight + y = twelve y = 5 The circumcenter try (7, 5)

Explanation: NQ = NR = NS 2x + step 1 = 4x – 9 4x – 2x = 10 2x = ten x = 5 NQ = ten + step one = 11 NS = eleven

Explanation: NU = NV = NT -3x + 6 = -5x -3x + 5x = -six 2x = -6 x = -step 3 NT = -5(-3) = 15

Explanation: NZ = Nyc = NW 4x – 10 = 3x – 1 x = 9 NZ = 4(9) – ten = thirty six – 10 = twenty-six NW = 26

Discover the coordinates of the centroid of your triangle wilt the new given vertices. http://www.datingranking.net/tr/ashley-madison-inceleme Question nine. J(- step one, 2), K(5, 6), L(5, – 2)

Let An excellent(- 4, 2), B(- cuatro, – 4), C(0, – 4) function as vertices of your own offered triangle and you can help P(x,y) be the circumcentre of the triangle

Explanation: The slope of TU = \(\frac < 1> <0>\) = -2 The slope of the perpendicular line is \(\frac < 1> < 2>\) The perpendicular line is y – 5 = \(\frac < 1> < 2>\)(x – 2) 2y – 10 = x – 2 x – 2y + 8 = 0 The slope of UV = \(\frac < 5> < 2>\) = 2 The slope of the perpendicular line is \(\frac < -1> < 2>\) The perpendicular line is y – 5 = \(\frac < -1> < 2>\)(x + 2) 2y – 10 = -x – 2 x + 2y – 8 = 0 equate both equations x – 2y + 8 = x + 2y – 8 -4y = -16 y = 4 x – 2(4) + 8 = 0 x = 0 So, the orthocenter is (0, 4) The orthocenter lies inside the triangle TUV