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Tool Rates – Guided Practice – Webpage No. 120

Question 1. Brandon enters bike races. He bikes 8 \(\frac<1><2>\) miles every \(\frac<1><2>\) hourplete the table to find how far Brandon bikes for each time interval

Answer: 1 hour: 8 \(\frac<1><2>\) + 8 \(\frac<1><2>\) = 17 1 \(\frac<1><2>\) hour: 17 + 8 \(\frac<1><2>\) = 25 \(\frac<1><2>\) 2 hour: 25 \(\frac<1><2>\) + 8 \(\frac<1><2>\) = 34 2 \(\frac<1><2>\) hour: 34 + 8 \(\frac<1><2>\) = 42 \(\frac<1><2>\)

Explanation: Divide the number of miles by the number of hours to find the unit rate in miles per hour. 3 \(\frac<1><2>\) ? 1 \(\frac<1><4>\) = \(\frac<7><2>\)/\(\frac<5><4>\) \(\frac<7><2>\) ? \(\frac<4><5>\) = \(\frac<14><5>\) Convert from improper fraction to the mixed fraction. \(\frac<14><5>\) = 2 \(\frac<4><5>\) miles per hour

Explanation: Divide the number of pages by the number of minutes to find the unit rate in pages per minute. \(\frac<5><8>\) ? \(\frac<2><3>\) = \(\frac<5><8>\) ? \(\frac<3><2>\) = \(\frac<15><16>\) Thus Kenny read \(\frac<15><16>\) pages per minute.

Explanation: Given that, A garden snail moves \(\frac<1><6>\) foot in \(\frac<1><3>\) hour. Divide the number of feet by the number of hours to find the unit rate in feet per hour. \(\frac<1><6>\) ? \(\frac<1><3>\) \(\frac<1><6>\) ? \(\frac<3><1>\) = \(\frac<1><2>\) Therefore A garden snail moves \(\frac<1><2>\) feet per hour.

Explanation: Given, A fertilizer covers \(\frac<5><8>\) square foot in \(\frac<1><4>\) hour. Divide the number of square feet, which is \(\frac<5><8>\) by the number of hours, which is \(\frac<1><4>\), to find the unit rate in square feet per hour. \(\frac<5><8>\) ? \(\frac<1><4>\) \(\frac<5><8>\) ? \(\frac<4><1>\) =\(\frac<5><2>\) Convert from improper fraction to the mixed fraction. \(\frac<5><2>\) = 2 \(\frac<1><2>\) square feet per hour Thus A fertilizer covers 2 \(\frac<1><2>\) square feet per hour.

Question 6. Brand A: 240 mg sodium for \(\frac<1><3>\) pickle or Brand B: 325 mg sodium for \(\frac<1><2>\) pickle. ____________

Answer: Find the unit rates in mg per pickle for each brand by dividing the number of mg by the number of pickles. Brand A: 240 mg ? \(\frac<1><3>\) = 240 ? 3 = 720 Brand B: 325 mg ? \(\frac<1><2>\) = 325 ? 2 = 650 650 is less than 720 so Brand B has a lower unit rate.

Answer: Find the unit rates in cups per serving by dividing the number of cups by the number of servings. Ingredient C: \(\frac<1><4>\) ? \(\frac<2><3>\) \(\frac<1><4>\) ? \(\frac<3><2>\) = \(\frac<3><8>\) Ingredient D: \(\frac<1><3>\) ? \(\frac<3><4>\) \(\frac<1><3>\) ? \(\frac<4><3>\) = \(\frac<4><9>\) \(\frac<3><8>\) is less than \(\frac<4><9>\), ingredient C has a lower unit rate.